I got the answer 1.125grams.
Please help!
If a .750g sample of magnesium chloride is dissolved in water and then treated with a silver nitrate solution how many grams of silver chloride should be collected?
I don't understand what my first step should be.
The balanced equation is
MgCl2+2AgNO3=2AgCl+Mg (NO3)2
Do I have to convert to moles? Please help.
2 answers
0.750g of MgCl2*(1 mol/95.211g)=0.007877 mol of MgCl2
*****1 mol of MgCl2=2 moles of AgCl
This is the key and is where your error lies.
0.007877 mol of MgCl2*(2 mol of AgCl/MgCl2)=0.01575 moles of AgCl
0.01575 moles of AgCl*(143.32 g/mol)=2.26g of AgCl
Best
*****1 mol of MgCl2=2 moles of AgCl
This is the key and is where your error lies.
0.007877 mol of MgCl2*(2 mol of AgCl/MgCl2)=0.01575 moles of AgCl
0.01575 moles of AgCl*(143.32 g/mol)=2.26g of AgCl
Best
4 answers