A sample that is 63.9 % chloride by mass is dissolved in water and treated with an excess of AgNO3. If the mass of the AgCl precipitate is 1.045g, what was the mass of the original sample?

Answer 1

1.045 g AgCl x (atomic mass Cl/molar mass AgCl) = approx 0.26 g Cl^- but you need to do it more accurately.
Then [0.26/(mass sample)]*100 = 63.9%
Solve for mass sample.

Answer 2

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