If 50.0 g of silicon dioxide is heated with an excess of carbon, 27.9g of silicon carbide is produced.

Question

SiO2(s) + 3C(s) --> SiC(s) + 2CO(g)

what is the percent yield of this reaction?

Answer 1

Convert 50.0 g SiO2 to moles. moles = grams/molar mass

Using the coefficients in the balanced equation, convert moles SiO2 to moles SiC.

Convert moles SiC to grams. grams = moles x molar mass. This is the theoretical yield of SiC in the reaction.

%yield = (actual yield/theoretical yield)*100 = ??

The actual yield given in the problem is 27.9 grams SiC.

Answer 2

The short answer is 34.53%

Answer 3

50 g SiO2 x 1mol SiO2 x 1mol SiC x 40.11g SiC = 33.4g SiC
60.08g SiO2 1mol SiO2 mol SiC
27.8g = 0.0832 = 83.5%
33.4g