WHEN 54.8g OF SILICON (iv) OXIDE IS HEATED WITH EXCESS OF CARBON, 32.5g OF SILICON CARBIDE IS PRODUCED BESIDS THE CARBON MONOXIDE GAS. WHAT IS THE PERCENTAGE YIELD OF THIS REACTION

Answer 1

SiO2 + 3C ==> SiC + 2CO
mols SiO2 = grams/molar mass = 54.8/60.08 = 0.912
From the coefficients in the equation you know 1 mol SiC is produced for every mole of SiO2; therefore, you will botain 0.912 mols SiC. Convert to grams. grams SiC = mols SiC x molar mass SiC = 0.912 x 40.09 = about 36.6 g SiC. That is the theoretical yield (TY). The actual yield (AY) is 32.5 from the problem.
% yield = (AY/TY)*100 = ?Check my arithmetic.

Answer 2

59.2%