If 225.O grams of NO react with excess NH3,how many grams of H2O are produced

Answer 1

The molecular formula is as followed:

6NO + 4NH3 --->5N2 + 6H2O

The ratio of moles of NO to H2O is 1 to 1.

225.0g of NO/30.01 g of NO/mol= moles of NO

Moles of NO=Moles of H20

Moles of H2O *18.02g of H2O/mol= mass of H2O