I need help with the following question: While fishing on a lake, you see a fish below water at a 25 degree angle with the surface, producing air bubbles on the surface of the water 20 feet ahead. How far away is the fish from the boat?

1 answer

Assuming we are not taking Snell's Law into account, the distance d is given by

sec 25° = x/20
x = 22.07 ft
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