Question
In a pristine lake with carrying capacity K and fishing allowed, the logistic differential equation for the population N(t) of fish at time t(in days) is dN/dt= rN(1-(N/K) - H.
H= the fish harvested from the lake each day.
If H= 3/16rK find all of the equilibria for the differential equation.
*I got (1/4) and (3/4).
What will happen to the fish population after a long time if the current population equals half of the carrying capacity?
*Do I solve the differential here?
If the rate of fish harvested is increased from H=3/16 rK fish per day to a larger number, how will the curve that you drew be affected ?
*The graph(dN/dt vs N) I drew is an upside down parabola shape that goes through the x-axis at (1/4) and (3/4)
If H is large enough, then the fish populations is guaranteed to go extinct. Find the smallest value of H for which the fish population is guaranteed to go extinct.
*No idea how to do this question
H= the fish harvested from the lake each day.
If H= 3/16rK find all of the equilibria for the differential equation.
*I got (1/4) and (3/4).
What will happen to the fish population after a long time if the current population equals half of the carrying capacity?
*Do I solve the differential here?
If the rate of fish harvested is increased from H=3/16 rK fish per day to a larger number, how will the curve that you drew be affected ?
*The graph(dN/dt vs N) I drew is an upside down parabola shape that goes through the x-axis at (1/4) and (3/4)
If H is large enough, then the fish populations is guaranteed to go extinct. Find the smallest value of H for which the fish population is guaranteed to go extinct.
*No idea how to do this question
Answers
oobleck
yesh - why don't we get part B at this point. Solve the DE.
Also, you might google logistic growth to see how the other parameters are used.
Also, you might google logistic growth to see how the other parameters are used.
anon
ummm could you possibly walk me through on how i would solve the DE...?
Thank you for your response!
Thank you for your response!