Could someone please correct my work.

Question

A fishing magazine collected data and printed the following results:
If there is rain then the probability of catching a fish at Lake Blue is 80%, but if it doesn't rain then the probability of catching a fish at Lake Blue is 17%. The forecast for today is 68% chance of rain.

A) Draw a tree diagram
(sorry if it looks confusing)
Percent = 100%
80%
R / / 17% R
/----------
| . \ 83 R (not)
|
| . 68% R
\ . /
\ ----------
R (not rain) . \
20% . 32% R(not)

b) What is the probability that it rained today and a fish was caught?
P(RR) = 0.20 x 0.68 = 0.136

c) What is the probability of catching a fish today?
P(R not R|R) = 0.20 x 0.68 = 0.136

d) IIf a person caught a fish, what is the probability that there was rain?
I don't get this question*

Thanks

Answer 1

R is 20%, not rain 32% and R = 68%