I need help, can someone guide me through this problem?

Question

log3(x + 2) + log3(4x – 1) = 5

Answer 1

sum of logs is log of product

log3 (4 x^2 + 7 x -2) = 5

base ^logbase(z) = z
so
3^[log3 (4 x^2 + 7 x -2)] = 3^5
or
(4 x^2 + 7 x -2) = 243

4 x^2 + 7 x - 245 = 0

(x-7)( 4x+35) = 0

x = 7 or x = -35/4

Answer 2

thank u so much!!! honestly u don't know how much u helped me :)

Answer 3

You are welcome, good luck :)