Find the emf with faradays law:
emf=-N*area*dB/dt
then, power= emf^2/resistance
where resistance= resistance/length*2PI*radius
I know I have posted this question before but I have tried everything under the sun to no avail. Please help a clueless student!!!!
A piece of copper wire is formed into a single circular loop of radius 13 cm. A magnetic field is oriented parallel to the normal to the loop, and it increases from 0 to 0.70 T in a time of 0.45 s. The wire has a resistance per unit length of 3.3 10-2 /m. What is the average electrical energy dissipated in the resistance of the wire.
__________J
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1 answer