since cotØ = 1/tanØ
tanØ = -1/8.91 = appr -.1122
We know that the tangent is negative in quads II and IV
the angle in standard position is 6.4°
so our angles are 180 - 6.4 = 173.6
or the angles is 360-6.4 = 353.6°
check one of them (353.6°)
cot 353.6° = 1/tan 353.6 = -8.91 , ok then!!
I can't seem to get the right answer on my assignment. I keep on getting 276.403 and seem to get it wrong. Please help.
Suppose that cot(θ)=−8.91 and 0∘≤θ<360∘
Find the two distinct angles.
1 answer
1 answer