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How to solve this 5x-19=2y,3y+18=4x

4 answers

5x-19=2y
3y+18=4x

5x-2y=19
4x-3y=18

15x-6y=57
8x-6y=36
--------------
7x=21
and so on

why a separate cryptic post just saying "substitution method"?
5x-19=2y, so y = (5x-19)/2

3y+18=4x
3(5x-19)/2+18=4x
15x-57+36=8x
7x = 21
x = 3
y = (5*3-19)/2 = -2

SOLVING

4x + 6y = 21
7x - 3y = 3

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