how to solve 3^(x-2) = 5^x

2 answers

well, you need to get the x stuff isolated, so get rid of those exponents:

(x-2) log3 = x log5
x(log3-log5) = 2log3
x = 2log3/(log3-log5) = log9/log(3/5) = log_{_3/5}9

Thanks

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