Work is Force multiplied by distance.
1250*105=?
Your answer will be in watts.
How much work must be done to stop a 1250 kg car traveling at 105 km/h?
9 answers
So then you have to convert it to joules?
131,250
531684.027J
you will first of all conevert km/h to m/s which is 105 multiply 1000 then divide by 3600= 29.7.
use the formula f= ma.
1250 multiply by 9.8=12250
then use formula for work
w=f multiply by distance
w=12250 multiply by 29.7=363825J.
use the formula f= ma.
1250 multiply by 9.8=12250
then use formula for work
w=f multiply by distance
w=12250 multiply by 29.7=363825J.
5.3xă10ă^5 J
physics sucks
-531685J
First convert km/h to m/s because we need the answer to be J, which is Kg/m^2/s^2
105km/h=29.2 m/s (the rule is, to go from km/h to m/s is divide by 3.6)
W=1/2mv^2
W=(0.5)(1250)(29.2)^2
W=531684J
AND, because the work is being done to slow something down, it is negative.
So the answer is -531684J. (the comment above me is correct, I just wanted to provide an explanation for anyone who wanted to know how he/she above me got to the correct answer)
105km/h=29.2 m/s (the rule is, to go from km/h to m/s is divide by 3.6)
W=1/2mv^2
W=(0.5)(1250)(29.2)^2
W=531684J
AND, because the work is being done to slow something down, it is negative.
So the answer is -531684J. (the comment above me is correct, I just wanted to provide an explanation for anyone who wanted to know how he/she above me got to the correct answer)
1 answer