The distance needed to stop a car (d) varies directly with the aquare of the speed of the car (s). If a car traveling 25 mph requires 0 feet to stop, how many feet will be required to stop a car that is traveling at 60 mph?

Answer 1

d = k v^2
when v=25, d= 0 ????

you see to have a typo .

suppose you meant to type d=50
then
50 = k(25)^2
k = 50/625 = 1/25

d = (1/25) v^2
so when v= 60
d = (1/25)(3600) = 144

Once you have determined what your typo was, replace the 50 in my solution with the correct value of d

Answer 2

the stopping distance D varies directly with the square of the speed S. if a car traveling 50mph has a stopping distance of 250 feet, find the stopping distance of 60mph.

Answer 3

What is k in this solution

Answer 4

300