How many moles of O2 are present in 67.2 L of O2 gas at STP?

Answer 1

what is 67.2/22.4 ?

Answer 2

using equation PV=nRT. and the STP of T=273K and P=1atm. You have your V=67.2L and R is always .0821(atm/L)(mol/K). Your equation will end up to be n=PV/RT. And if I calculated rite your mole will be rounded to 3. But please check

Answer 3

As we know the no of moles at STP =volume in lt at STP/22.4lt so as per this,
67.2/22.4=3 moles