What's the reaction? I'm guessing at
Ag^+ + 2NH3 ==> Ag(NH3)2^+
If that's the reaction my number is 1.75E7 which I would round to 1.8E7 instead of your 1.7E7. Good work.
An experiment was carried out to determine the value of the equilibrium constant Kc for the reaction.
Total moles of Ag+ present = 3.6 x 10-3 moles
Total moles of NH3 present = 6.9 x 10-3 moles
Measured concentration of Ag(NH3)2+ at equilibrium= 3.4* 10-2 M
Total solution volume = 100 mL
(a). Calculate the equilibrium concentration of Ag+ (uncomplexed).
(b). Calculate the equilibrium concentration of NH3 (uncomplexed).
(c). Calculate the value of the equilibrium constant (Kc).
I GOT 1.7*10^7 for question C. IS IT RIGHT?????????
4 answers
THANX
uju
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