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How many Ml of 0.200 M NaOH are needed to neutralize 15.00 mL of the 0.100 M hypothetical acid H2A?

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H2A + 2NaOH ==> NaA + 2H2O
mols H2A = M x L = ?
1 mol H2A = 2 mols NaOH; therefore, mols NaOH = mols H2A x 2 = ?
Then M NaOH = mols NaOH/L NaOH. You know mols NaOH and M NaOH, solve for L NaOH and convert to mL.

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