How many mols acetic acid did you use? That's M x L = ?
Now use the equation coefficients to convert mols acetic acid to mols NaOH. That's a 1:1 ratio; therefore, mols NaOH = same as mols acetic acid.
Then M NaOH = mols NaOH/L NaOH. You have mols and M NaOH, solve for L NaOH and convert to mL.
In the titration of 14.0 mL of 0.10M acetic acid with 0.40 M NaOH,
(A) How many mL of NaOH needed to completely neutralize the acid? Given the balanced equation:
CH3COOH (aq) + NaOH (aq) CH3COO Na (aq) + H2O
1 answer