How long will it take a 2.30 x 10^3 kg truck to go from 22.2 m/s to a complete stop if acted on by a force of -1.26 x 10^4 N? what would be its stopping distance?

Answer 1

F*time=mass*changeinvelocity
solve for time.
for distance...
1/2 m vi^2= force*distance solve for distance.