Ask a New Question
Menu

How do you simplify the formula (v^2sinxcosx)/2g?

1 answer

not much to do here.
the only thing would be to change the sincosx to (1/2)sin (2x)
so you could have:
v^2 sin(2x)/(4g), but I don't see that as any more "simplified"
Similar Questions
  1. Is this correct?(sinx - cosx)^2 = 1 - 2sinxcosx LS = sin^2x - 2sinxcosx + cos^2x = 1 - cos^2x - 2sinxcosx + cos^2x = 1 - cos^2x
    1. answers icon 0 answers
  2. Is this correct?(sinx - cosx)^2 = 1 - 2sinxcosx LS = sin^2x - 2sinxcosx + cos^2x = 1 - cos^2x - 2sinxcosx + cos^2x = 1 - cos^2x
    1. answers icon 1 answer
  3. Prove the identity:1-cos2x/sin2x = 1+tanx/1+cotx I simplified the RS to tanx. LS:(1-2cos²x+1)/2sinxcosx (2+2cos²x)/2sinxcosx
    1. answers icon 2 answers
  4. solve algebraically, express the roots in exact form2sinxcosx-1=0 I got: 2sinxcosx=1 sin^2x=1 what do I do next? thanks in
    1. answers icon 0 answers
more similar questions