Prove the identity:

1-cos2x/sin2x = 1+tanx/1+cotx

I simplified the RS to tanx.
LS:(1-2cos²x+1)/2sinxcosx
(2+2cos²x)/2sinxcosx

How do I simplify the rest?

2 answers

change the LS to
(1 - (1 - 2sin²x))/(2sinxcosx)
= 2sin²x/(2sinxcox)
= sinx/cosx
= tanx = RS
thanks! I've been trying to get this one for quite awhile. So many options to choose :(
Similar Questions
  1. Solve identity,(1-sin2x)/cos2x = cos2x/(1+sin2x) I tried starting from the right side, RS: =(cos²x-sin²x)/(1+2sinxcosx)
    1. answers icon 3 answers
  2. Prove the identityCos²x - sin²x = 2cos²x - 1
    1. answers icon 1 answer
  3. tan(X+30)tan(30-x)=2cos2x-1 / (2cos2x+1)i just did (tanx)(-tanx)=-sin^2x/cos^2x would that work?
    1. answers icon 2 answers
    1. answers icon 1 answer
more similar questions