Is this correct?

(sinx - cosx)^2 = 1 - 2sinxcosx
LS = sin^2x - 2sinxcosx + cos^2x
= 1 - cos^2x - 2sinxcosx + cos^2x
= 1 - cos^2x + cos^2x - 2sinxcosx
= 1 - 2sinxcosx

LS = RS

Similar Questions
  1. Is this correct?(sinx - cosx)^2 = 1 - 2sinxcosx LS = sin^2x - 2sinxcosx + cos^2x = 1 - cos^2x - 2sinxcosx + cos^2x = 1 - cos^2x
    1. answers icon 1 answer
  2. Solve for [0, 360)2sinxcosx + cosx =0 2sinxcosx = -cosx 2sinx = -cosx/cosx sinx = -1/2 {210, 330) Is this correct?
    1. answers icon 1 answer
    1. answers icon 3 answers
  3. sin2x+cosx=0 , [-180,180)= 2sinxcosx+cosx=0 = cosx(2sinx+1)=0 cosx=0 x1=cos^-1(0) x1=90 x2=360-90 x2=270 270 doesn't fit in
    1. answers icon 1 answer
more similar questions