y = mx + b
y is -2
slope (m) is 2
x is -8.
Plug in the numbers. Solve for b.
Then write y = 2x + (value for b)
how do i do a problem like this and other problems like this:
Write an equation in point-slope form of the line that passes through the given point and has the given slope.
(-8,-2) M=2
12 answers
so it would be y+2=(X+8)?
That does not look like y = m x + b
i said POINT SLOPE FORM y+M=x+x
He said
y = m x + b
then since slope is 2
y = 2x + b
then he put x, y and m in
-2 = 2(-8) + b
Now solve for b
y = m x + b
then since slope is 2
y = 2x + b
then he put x, y and m in
-2 = 2(-8) + b
Now solve for b
but that is slope intersept form not point slope form
then
(y-Y1) = m (x -X1)
(y-Y1) = m (x -X1)
y - (-2) = 2 (x - (-8) )
y +2 = 2(x+8)
y +2 = 2(x+8)
so would it be y+2=2(x+8)????
Yes.
You are right. I gave you the slope intercept form.
y-y1 = m(x-x1)
y+2=2(x+8).
I don't know if your prof wants that expanded or not. This becomes
y = 2x + 14 in the slope intercept form so both equations are the same.
y-y1 = m(x-x1)
y+2=2(x+8).
I don't know if your prof wants that expanded or not. This becomes
y = 2x + 14 in the slope intercept form so both equations are the same.
no he dosen't thanks a lot