Asked by Lady T.
How can I find the equation in standard form using only integers for the line through (-1,-3) and (2,-1)?
Answers
Answered by
Reiny
first find the slope
slope (-3 + 1)/(-1-2) = 2/3
using the point (2,-1)
y+1 = (2/3)(x-2)
3y+3 = 2x-4
2x - 3y = 7
or
2x - 3y - 7 = 0 , depending what your course defines as "standard from"
slope (-3 + 1)/(-1-2) = 2/3
using the point (2,-1)
y+1 = (2/3)(x-2)
3y+3 = 2x-4
2x - 3y = 7
or
2x - 3y - 7 = 0 , depending what your course defines as "standard from"
Answered by
drwls
The slope is m = (-1 +3)/(2+1) = 2/3
So the equation in standard form is
y = (2/3)x + b
You still need to determine the constant b. Require that
-1 = (2/3)*2 +b
b = -7/3
Therefore
y = (2/3)x - 7/3
If you want integer coefficients only, you will have to write it as
3y = 2x - 7
So the equation in standard form is
y = (2/3)x + b
You still need to determine the constant b. Require that
-1 = (2/3)*2 +b
b = -7/3
Therefore
y = (2/3)x - 7/3
If you want integer coefficients only, you will have to write it as
3y = 2x - 7
Answered by
Lady T.
Ax+By=C
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