(a) the slope is 2, so use the point-slope form
y+1 = 2(x-2)
(b) Plot the points, and it is easy to see that P is SE of Q.
The bearing of P from Q would be 135°
(a)find the equation of the line which pass through the point (2,-1) and (1,-3).
(b)p(2,1) and Q(1,2)are point in the plane. find the bearing of P and Q
2 answers
(2, -1), (1, -3).
a. m = (-3+1)/(1-2) = 2.
y = mx+b.
-1 = 2*2+b
b = -5.
y = 2x-5.
b. P(2, 1), Q(1, 2).
m = Tan A = (1-2)/(2-1) = -1.
A = -45o = 315o CW from +y-axis(Bearing of P and Q).
A = 135o CCW from +x-axis.
a. m = (-3+1)/(1-2) = 2.
y = mx+b.
-1 = 2*2+b
b = -5.
y = 2x-5.
b. P(2, 1), Q(1, 2).
m = Tan A = (1-2)/(2-1) = -1.
A = -45o = 315o CW from +y-axis(Bearing of P and Q).
A = 135o CCW from +x-axis.
1 answer