Asked by Godwin
(a)find the equation of the line which pass through the point (2,-1) and (1,-3).
(b)p(2,1) and Q(1,2)are point in the plane. find the bearing of P and Q
(b)p(2,1) and Q(1,2)are point in the plane. find the bearing of P and Q
Answers
Answered by
oobleck
(a) the slope is 2, so use the point-slope form
y+1 = 2(x-2)
(b) Plot the points, and it is easy to see that P is SE of Q.
The bearing of P from Q would be 135°
y+1 = 2(x-2)
(b) Plot the points, and it is easy to see that P is SE of Q.
The bearing of P from Q would be 135°
Answered by
henry2,
(2, -1), (1, -3).
a. m = (-3+1)/(1-2) = 2.
y = mx+b.
-1 = 2*2+b
b = -5.
y = 2x-5.
b. P(2, 1), Q(1, 2).
m = Tan A = (1-2)/(2-1) = -1.
A = -45o = 315o CW from +y-axis(Bearing of P and Q).
A = 135o CCW from +x-axis.
a. m = (-3+1)/(1-2) = 2.
y = mx+b.
-1 = 2*2+b
b = -5.
y = 2x-5.
b. P(2, 1), Q(1, 2).
m = Tan A = (1-2)/(2-1) = -1.
A = -45o = 315o CW from +y-axis(Bearing of P and Q).
A = 135o CCW from +x-axis.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.