looks like your base is x-2 and the height is x, so
(1/2)(x)(x-2) = 2.5
x(x-2) = 5
x^2 - 2x - 5 = 0
solve for x and take it from there
Here is a right- angled triangle.
|\
| \
x | \
|___\
x - 2
All measurements are in centimetres.
The area if the triangle is 2.5cm^2.
Find the perimeter of the triangle.
Key values:
Equation for area:
?
- __(___) = ?
?
Quadratic equation:
-b ± √b^2 - 4ac
-------------
2a
Solutions:
x = ? or ?
Length of the hypotenuse:
?
Perimeter
? + ? + ? = ? cm
Thanks
4 answers
Hi Reiny,
What would a, b and c be for the quadratic formula?
Thanks
What would a, b and c be for the quadratic formula?
Thanks
huh? a,b,c are the coefficients in the equation, as usual!
Edhbshan