The Perimeter of a right angled triangle is 40 CM. Find the area of the right angled triangle.

Answer 1

Not enough information
c^2 = a^2 + b^2

P = a + b + c = 40
or
P = a + b + sqrt(a^2+b^2) = 40

now if it is isoceles, a = b, then
P = 2 a + sqrt (2 a^2) = 3.414 a = 40

A = (1/2) a b = (1/2)a^2 = (1/2)(40/3.414)^2

= 68.6

Answer 2

Some information is needed