Asked by Sherlique
Hello,
Is there a reaction when NaNO3 is added to some H2O? Or does it just dissolves?
Please explain why, thanks!
Is there a reaction when NaNO3 is added to some H2O? Or does it just dissolves?
Please explain why, thanks!
Answers
Answered by
bobpursley
The reaction is the sodum nitrate breaks up in to ions, energy is exchanged.
Answered by
DrBob222
The solid NaNO3 is held together by the crystal lattice energy. The Na-NO3 is an ionic bond. When the polar water molecules of water move to the crystal, the positive end of the H2O molecules is attracted to the NO3^- part of the NaNO3 and the negative end of the H2O molecule is attracted to the Na^+. The Na^+ becomes hydrated as Na^+(aq) and the NO3^- becomes hydrated as NO3^-(aq). You might write the equation as
NaNO3(s) + H2O(l) ==> Na^+(aq) + NO3^-(aq)
There are many articles and some movies on the internet that talk about this process. You can google to read more about it.
NaNO3(s) + H2O(l) ==> Na^+(aq) + NO3^-(aq)
There are many articles and some movies on the internet that talk about this process. You can google to read more about it.
Answered by
Sherlique
Hi DrBob222,
Can I express it in this form?
NaNO3(s) + H2O(l) ==> NaNO3(aq)
Can I express it in this form?
NaNO3(s) + H2O(l) ==> NaNO3(aq)
Answered by
DrBob222
Yes, and that might be called an intermediate step, with the final step showing the hydratred ions.
Answered by
Sherlique
How about if I put the "H2O" above the arrow, and wrote NaNO3(aq) as my answer, would that be correct?
Answered by
DrBob222
Yes.
Answered by
Sherlique
Thanks!
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