mols NaNO3 needed = grams/molar mass.
Using the coefficients in the balanced equation, convert mols NaNO3 to mols Pb(NO3)2. In this case that's mols NaNO3 x (1 mol Pb(NO3)2/2 mols NaNO3) = x mols NaNO3 x (1/2) = ?
In the following reaction, how many grams of lead(II) nitrate Pb(NO3)2 will produce 425 grams of sodium nitrate (NaNO3)?
Pb(NO3)2(aq) + 2 NaBr(aq) PbBr2(s) + 2 NaNO3(aq)
The molar mass of Pb(NO3)2 is 331.21 grams and that of NaNO3 is 85 grams.
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hgmgyk
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