tan^2x + 2tanx -3 = 0
(tanx-3)(tanx+1) = 0
tanx = 3
tanx = -1
Now just find where tanx has those values
Hello I am trying to solve the equation:
tan^(2)x + 2tanx -3 = 0
the first part says tangent squared times x
the second part is 2 times tangent x
1 answer