Actually you don't need to simplify the tan2x. If you move 1 over to the other side to get -1 then you just need to find the tan of -1.
According to the unit circle this gives you three pi fourths + npi and 7 pi fourths + npi (remember the period of the tangent function is 2). Then just divide those two values by 2 because your equation is still equated to 2x.
Then you have your answers!
Hope this helped
I keep trying to solve this by factring but I can't seem to get! It's so frustrating!
The problem is 1+tan2x=0
This is how I worked the problem before:
1+((2tanx)/(1-tan^2x))=0
((2tanx)/(1-tan^2x))= -1
Then I cross multiplied to get:
-1 + tan^2x = 2 tanx
Than I rearranged everything like so...
tan^2x - 2tanx -1 =0
Then I tried to factor it but it wouldn't work. Is there something wrong with my work?
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