Asked by Anonymous
find the derivative of the functions F(x)= tan^2(x) and G(x) = sec^2(x).... based on your calculations what can you say about F(x) - G(x)
I found F'x =2 secx^2tanx
G'(x)= 2secx^2tanx then when subtracted they equal zero, is there more explanation for this?
I found F'x =2 secx^2tanx
G'(x)= 2secx^2tanx then when subtracted they equal zero, is there more explanation for this?
Answers
Answered by
oobleck
yes.
sec^2x - tan^2x = 1
so of course the derivative is zero.
sec^2x - tan^2x = 1
so of course the derivative is zero.
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