...................HA ==> H^+ + A^-
I..................3.0.........0.........0
C................-x............x.........x
E................3.0-x.......x.........x
Write the K expression, plug in the numbers and solve for x. Use the value of x to determine the values of HA, H^+ and A^-.
Post your work if you get stuck.
HA(aq) <-> H+(aq) + A-(aq) K = 5.0 x 10 -9
The initial concentration of HA is 0.30 M What is the final equilibrium concentrations of HA, H+, A-?
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1 answer