What would be the concentration of dinitrogen pentoxide after 6.00 X 10(2) seconds and how long would it take for the concentration of N2O2 to decrease to 10.0% of its initial value in the following equation...

Question

N2O5 to NO2 and O2

initial concentration is 1.65 X 10-2mol/L

rate constant is 4.80 X 10-4/s
time is 825s

According to my book, the answer is 1.24 X 10-2 mol/L and t= 4.80 X 10 (3)s

I have no idea how to set this problem up with the 1st order rate law...

Answer 1

This is a first order reaction (you know that from the units given for k).
ln(No/N) = kt
ln(0.0165/N) = 4.80E-4*600
Solve for N.
Use the same equation. No is the same, N is 10% of that, k is the same, solve for t.
Check my work for typos.

Answer 2

A vessel containing 39.5 cm3 of helium gas at 25°C and 106 kPa was inverted and placed in cold ethanol. As the gas contracted, ethanol was forced into the vessel to maintain the same pressure of helium. If this required 17.8 cm3 of ethanol, what was the final temperature of the helium?

Answer 3

many mols He were in the container? That's PV = nRT. Solve for n. Use that n in another PV = nRT. You know P,
V = 39.5cc - 17.8cc
R and solve for T.
Rememberr V must be i L, R is 0.08206 if you use P in atm or 8.314 if you use P in kPa. T must be in kelvin.

Answer 4

You should not piggy back your question on another post. Go to the top of the page and click on "Post a New Question."

Answer 5

So, to solve for t would I set up the problem like this...

ln (0.00124/0.0165)=4.80 X 10-4 X t?