you can group factor
(3x^5+2x^4)=x^4(3x+2)
(15x^3+10^2)=5x^2(3x+2)
(-528x-352)=-176(3x+2)
(3x+2)(x^4+5x^2+176)and continue from here
h(x)= 3x^(5) + 2x^(4) + 15x^(3) + 10x^(2) - 528x - 352
for this equation how would I know to use the square root of 11 in synthetic division to be a factor?
I used the p / q list but I did not get sqt root of 11 as a possible factor.
could someone help please.
3 answers
How do I solve 2x-4=x-10?
bro what