hh? If you have the graphs, just mark where the lines intersect. I assume your graph looked kind of like this:
http://www.wolframalpha.com/input/?i=plot+y-2x%E2%89%A5-3,+y%2B3%3E%E2%88%92x,+3y%E2%88%922%E2%80%8Bx%E2%89%A412,+2y%2Bx%3C8
Now, the lowest vertex is the intersection of the lines
y-2x = -3
y+3 = -x
Pick other pairs of lines and you can find the other vertex coordinates.
Graph the system of inequalities, and label each with a vertex with its coordinates.
y-2x≥-3
y+3>−x
3y−2x≤12
2y+x<8
I did graph this but I'm having a hard time to label each vertex with its coordinates.
3 answers
Yes it did. However, the points I found don't match the answer when I plug x and y back in the equation
For ex. Point (0, 4) that works in the equation 3 and 4.
Point (-4.25,1.25) does not work in equation 2 and 3.
Point (0,-3) does not work in equation 1 and 2
Point (2.75,2.5) does not work on eqaution 1 and 4.
For ex. Point (0, 4) that works in the equation 3 and 4.
Point (-4.25,1.25) does not work in equation 2 and 3.
Point (0,-3) does not work in equation 1 and 2
Point (2.75,2.5) does not work on eqaution 1 and 4.
so, if those points do not work, why are you mentioning them? Surely you can find the intersections of two lines ... ?? Got some work to show?
There are 6 pairs of lines, but two of them intersect outside the shaded region.
There are 6 pairs of lines, but two of them intersect outside the shaded region.