Asked by tyneisha
Graph the system of inequalities then substitute the (x,y)order pair into both inequalities.
y>3x+1
y<-2/3x+4
(second one has a line under the arrow)
I don't get what they are asking for? if they want me to solve it how am I suppose to set it up?
y>3x+1
y<-2/3x+4
(second one has a line under the arrow)
I don't get what they are asking for? if they want me to solve it how am I suppose to set it up?
Answers
Answered by
Steve
You know how to graph the line
y = 3x+1
y > 3x+1 is everything where y is above the line.
Similarly, y <= -2/3 x + 4
is everything below that line, and including the line itself.
Take a trip to wolframalpha.com and enter
solve y > 3x + 1, y <= -2/3 x + 4
It will graph the region in blue which is above one line and below the other.
y = 3x+1
y > 3x+1 is everything where y is above the line.
Similarly, y <= -2/3 x + 4
is everything below that line, and including the line itself.
Take a trip to wolframalpha.com and enter
solve y > 3x + 1, y <= -2/3 x + 4
It will graph the region in blue which is above one line and below the other.
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