To determine which function has a y-intercept, we need to evaluate each function at \(x=0\):
-
For \(f(x) = \sqrt{x - 2}\):
- \(f(0) = \sqrt{0 - 2} = \sqrt{-2}\), which is not a real number. Thus, \(f(x)\) has no y-intercept.
-
For \(g(x) = \sqrt{2 - x}\):
- \(g(0) = \sqrt{2 - 0} = \sqrt{2}\), which is a real number. Hence, \(g(x)\) has a y-intercept.
Based on this evaluation, the answer is:
Option 2: g(x)