To complete the table of data points for the function y=(1/3)sqrt(x-3+2), we need to substitute the given values of x into the function and evaluate the corresponding y values.
For x = 3:
y = (1/3)sqrt(3-3)+2
y = (1/3)sqrt(2)
y = (1/3)(√2)
y = √2/3
So, when x = 3, y = √2/3
For x = 4:
y = (1/3)sqrt(4-3)+2
y = (1/3)sqrt(3)
y = √3/3
So, when x = 4, y = √3/3
For x = 7:
y = (1/3)sqrt(7-3)+2
y = (1/3)sqrt(6)
y = √6/3
So, when x = 7, y = √6/3
Therefore, the completed table of data points for the function y=(1/3)sqrt(x-3+2) is:
x / y
3 / √2/3
4 / √3/3
7 / √6/3
to graph the square root function y=1/3\sqrt(x-3++2), complete the table of data points for the function.
x / y
3 / ?
4 / ?
7 / ?
5 answers
in decimals
To determine the decimal values for the data points when x = 3, 4, and 7 in the function y = (1/3)sqrt(x-3+2), we can calculate the values using a calculator.
For x = 3:
y = (1/3)√2 ≈ 0.471
For x = 4:
y = (1/3)√3 ≈ 0.577
For x = 7:
y = (1/3)√6 ≈ 0.816
Therefore, the completed table of data points for the function y = (1/3)sqrt(x-3+2) in decimals is:
x / y
3 / 0.471
4 / 0.577
7 / 0.816
For x = 3:
y = (1/3)√2 ≈ 0.471
For x = 4:
y = (1/3)√3 ≈ 0.577
For x = 7:
y = (1/3)√6 ≈ 0.816
Therefore, the completed table of data points for the function y = (1/3)sqrt(x-3+2) in decimals is:
x / y
3 / 0.471
4 / 0.577
7 / 0.816
THat's not right
Apologies for the error. Let's correct it.
For x = 3:
y = (1/3)√(3-3+2)
y = (1/3)√2
y = √2/3 ≈ 0.4714
For x = 4:
y = (1/3)√(4-3+2)
y = (1/3)√3
y = √3/3 ≈ 0.5774
For x = 7:
y = (1/3)√(7-3+2)
y = (1/3)√6
y = √6/3 ≈ 0.8165
The corrected table with the approximate decimal values for the function y = (1/3)sqrt(x-3+2) is:
x / y
3 / 0.4714
4 / 0.5774
7 / 0.8165
For x = 3:
y = (1/3)√(3-3+2)
y = (1/3)√2
y = √2/3 ≈ 0.4714
For x = 4:
y = (1/3)√(4-3+2)
y = (1/3)√3
y = √3/3 ≈ 0.5774
For x = 7:
y = (1/3)√(7-3+2)
y = (1/3)√6
y = √6/3 ≈ 0.8165
The corrected table with the approximate decimal values for the function y = (1/3)sqrt(x-3+2) is:
x / y
3 / 0.4714
4 / 0.5774
7 / 0.8165
1 answer