Question

To graph the square root function y=−2x+1−−−−√−3
, complete the table of data points for the function.(2 points)
x y
−1
0
3

Answer 1

is 1 -5 -7 the answer

Answer 2

so whats the answer

Answer 3

To find the values of \( y \) for the function \( y = \sqrt{-2x + 1} - 3 \), we need to evaluate the expression for each given \( x \) in the table.

1. **For \( x = -1 \)**:
\[
y = \sqrt{-2(-1) + 1} - 3 = \sqrt{2 + 1} - 3 = \sqrt{3} - 3 \approx -1.268
\]

2. **For \( x = 0 \)**:
\[
y = \sqrt{-2(0) + 1} - 3 = \sqrt{0 + 1} - 3 = \sqrt{1} - 3 = 1 - 3 = -2
\]

3. **For \( x = 3 \)**:
\[
y = \sqrt{-2(3) + 1} - 3 = \sqrt{-6 + 1} - 3 = \sqrt{-5}
\]
Since the square root of a negative number is not defined in the real number system, \( y \) is not defined for \( x = 3 \).

Now we can fill in the table:

\[
\begin{array}{|c|c|}
\hline
x & y \\
\hline
-1 & \sqrt{3} - 3 \approx -1.268 \\
0 & -2 \\
3 & \text{undefined} \\
\hline
\end{array}
\]

So, the completed table is:

\[
\begin{array}{|c|c|}
\hline
x & y \\
\hline
-1 & -1.268 \\
0 & -2 \\
3 & \text{undefined} \\
\hline
\end{array}
\]

Answer 4

Let's clarify the function \( y = \sqrt{-2x + 1} - 3 \) and evaluate it for the \( x \) values you provided. We will check for \( x = -1 \), \( x = 0 \), and \( x = 3 \).

1. **For \( x = -1 \)**:
\[
y = \sqrt{-2(-1) + 1} - 3 = \sqrt{2 + 1} - 3 = \sqrt{3} - 3 \approx -1.268
\]
This value does not match any integers.

2. **For \( x = 0 \)**:
\[
y = \sqrt{-2(0) + 1} - 3 = \sqrt{1} - 3 = 1 - 3 = -2
\]
This is not \( -5 \) or \( -7 \).

3. **For \( x = 3 \)**:
\[
y = \sqrt{-2(3) + 1} - 3 = \sqrt{-6 + 1} - 3 = \sqrt{-5}
\]
This value is undefined in the real number system, again not fitting \( -5 \) or \( -7 \).

From the evaluations:

- The \( y \) value for \( x = -1 \) is approximately \( -1.268 \).
- The \( y \) value for \( x = 0 \) is \( -2 \).
- The \( y \) value for \( x = 3 \) is undefined.

It seems like the values \( 1, -5, -7 \) do not correspond with any of the function evaluations for the specified \( x \) values. Please confirm the expression given to analyze or provide further context if there is confusion.

Answer 5

Let's clarify and compute the \( y \) values for the function \( y = \sqrt{-2x + 1} - 3 \) at the specified \( x \) values:

1. **For \( x = -1 \)**:
\[
y = \sqrt{-2(-1) + 1} - 3 = \sqrt{2 + 1} - 3 = \sqrt{3} - 3 \approx -1.268
\]

2. **For \( x = 0 \)**:
\[
y = \sqrt{-2(0) + 1} - 3 = \sqrt{0 + 1} - 3 = \sqrt{1} - 3 = 1 - 3 = -2
\]

3. **For \( x = 3 \)**:
\[
y = \sqrt{-2(3) + 1} - 3 = \sqrt{-6 + 1} - 3 = \sqrt{-5} - 3
\]
Since we cannot take the square root of a negative number, \( y \) is undefined for \( x = 3 \).

**Final Results:**
- For \( x = -1 \), \( y \approx -1.268 \)
- For \( x = 0 \), \( y = -2 \)
- For \( x = 3 \), \( y \) is **undefined**

### Complete Table:

\[
\begin{array}{|c|c|}
\hline
x & y \\
\hline
-1 & \sqrt{3} - 3 \approx -1.268 \\
0 & -2 \\
3 & \text{undefined} \\
\hline
\end{array}
\]

If you were looking for specific integer values like \( 1, -5, -7 \), those do not correspond to the given function for the inputs provided. The values derived from the evaluation of the function are:
- \( y \approx -1.268 \) for \( x = -1 \)
- \( y = -2 \) for \( x = 0 \)
- Undefined for \( x = 3 \)