To graph the square root function y=−2x+1−−−−√−3

Question

, complete the table of data points for the function.(2 points)
x y
−1
0
3

Answer 1

To find the values of \( y \) for the function \( y = \sqrt{-2x + 1} - 3 \), we need to evaluate the expression for each given \( x \) in the table.

1. For \( x = -1 \): \[ y = \sqrt{-2(-1) + 1} - 3 = \sqrt{2 + 1} - 3 = \sqrt{3} - 3 \approx -1.268 \]

2. For \( x = 0 \): \[ y = \sqrt{-2(0) + 1} - 3 = \sqrt{0 + 1} - 3 = \sqrt{1} - 3 = 1 - 3 = -2 \]

3. For \( x = 3 \): \[ y = \sqrt{-2(3) + 1} - 3 = \sqrt{-6 + 1} - 3 = \sqrt{-5} \] Since the square root of a negative number is not defined in the real number system, \( y \) is not defined for \( x = 3 \).

Now we can fill in the table:

\[ \begin{array}{|c|c|} \hline x & y \ \hline -1 & \sqrt{3} - 3 \approx -1.268 \ 0 & -2 \ 3 & \text{undefined} \ \hline \end{array} \]

So, the completed table is:

\[ \begin{array}{|c|c|} \hline x & y \ \hline -1 & -1.268 \ 0 & -2 \ 3 & \text{undefined} \ \hline \end{array} \]

Answer 2

is 1 -5 -7 the answer

Answer 3

Let's clarify the function \( y = \sqrt{-2x + 1} - 3 \) and evaluate it for the \( x \) values you provided. We will check for \( x = -1 \), \( x = 0 \), and \( x = 3 \).

1. For \( x = -1 \): \[ y = \sqrt{-2(-1) + 1} - 3 = \sqrt{2 + 1} - 3 = \sqrt{3} - 3 \approx -1.268 \] This value does not match any integers.

2. For \( x = 0 \): \[ y = \sqrt{-2(0) + 1} - 3 = \sqrt{1} - 3 = 1 - 3 = -2 \] This is not \( -5 \) or \( -7 \).

3. For \( x = 3 \): \[ y = \sqrt{-2(3) + 1} - 3 = \sqrt{-6 + 1} - 3 = \sqrt{-5} \] This value is undefined in the real number system, again not fitting \( -5 \) or \( -7 \).

From the evaluations:

• The \( y \) value for \( x = -1 \) is approximately \( -1.268 \).
• The \( y \) value for \( x = 0 \) is \( -2 \).
• The \( y \) value for \( x = 3 \) is undefined.

It seems like the values \( 1, -5, -7 \) do not correspond with any of the function evaluations for the specified \( x \) values. Please confirm the expression given to analyze or provide further context if there is confusion.

Answer 4

so whats the answer

Answer 5

Let's clarify and compute the \( y \) values for the function \( y = \sqrt{-2x + 1} - 3 \) at the specified \( x \) values:

1. For \( x = -1 \): \[ y = \sqrt{-2(-1) + 1} - 3 = \sqrt{2 + 1} - 3 = \sqrt{3} - 3 \approx -1.268 \]

2. For \( x = 0 \): \[ y = \sqrt{-2(0) + 1} - 3 = \sqrt{0 + 1} - 3 = \sqrt{1} - 3 = 1 - 3 = -2 \]

3. For \( x = 3 \): \[ y = \sqrt{-2(3) + 1} - 3 = \sqrt{-6 + 1} - 3 = \sqrt{-5} - 3 \] Since we cannot take the square root of a negative number, \( y \) is undefined for \( x = 3 \).

Final Results:

• For \( x = -1 \), \( y \approx -1.268 \)
• For \( x = 0 \), \( y = -2 \)
• For \( x = 3 \), \( y \) is undefined

Complete Table:

\[ \begin{array}{|c|c|} \hline x & y \ \hline -1 & \sqrt{3} - 3 \approx -1.268 \ 0 & -2 \ 3 & \text{undefined} \ \hline \end{array} \]

If you were looking for specific integer values like \( 1, -5, -7 \), those do not correspond to the given function for the inputs provided. The values derived from the evaluation of the function are:

• \( y \approx -1.268 \) for \( x = -1 \)
• \( y = -2 \) for \( x = 0 \)
• Undefined for \( x = 3 \)