To determine which function has a y-intercept, we can evaluate both functions at \( x = 0 \).
For the function \( f(x) = \sqrt{x - 2} \):
- \( f(0) = \sqrt{0 - 2} = \sqrt{-2} \), which is not defined (the square root of a negative number).
For the function \( g(x) = \sqrt{2 - x} \):
- \( g(0) = \sqrt{2 - 0} = \sqrt{2} \), which is defined and is a real number.
Since \( f(x) \) does not have a y-intercept (it is not defined at \( x = 0 \)), while \( g(x) \) does, the correct answer is:
Option 2: g(x)