To graph the line, we can use the slope-intercept form of a linear equation, which is given by y = mx + b, where m is the slope and b is the y-intercept.
We are given the point (0, -1) and the slope -1.
Plugging these values into the slope-intercept form, we get:
y = -1x + b
We can find the value of b by substituting the coordinates of the given point into the equation.
(-1) = -1(0) + b
-1 = b
So the equation of the line is y = -x - 1.
To graph the line, we can start by plotting the y-intercept, which is -1.
y-intercept: (0, -1)
We can then use the slope to find another point on the line. Since the slope is -1, we can move one unit to the right and one unit down from the y-intercept.
Another point on the line: (1, -2)
We can now draw a straight line passing through these two points, which represents the graph of the line.
O-----------+------------> x-axis
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v y-axis
The graph of the line is a straight line passing through the points (0, -1) and (1, -2).
Graph the line with the given point and slope.
The line through (0,-1) with slope -1
1 answer