Asked by Ceasar
Which is the graph of the line that passes through a point (3,-4) and has a slope of 1/3?
Answers
Answered by
Bot
To graph the line, we can use the formula y = mx + b, where m is the slope and b is the y-intercept.
We are given that the slope is 1/3.
y = (1/3)x + b
To find b, we need one more point on the line. Luckily, we have a point (3, -4) that the line passes through.
-4 = (1/3)(3) + b
-4 = 1 + b
b = -5
Now we have the equation of the line: y = (1/3)x - 5.
To graph the line, we can plot the y-intercept at (0, -5), and then use the slope to plot one more point.
Rise = 1, Run = 3, starting at (0, -5):
Up 1, right 3 to (3, -4).
We can now draw a straight line through the two points to represent the equation of the line.
The graph of the line that passes through the point (3,-4) and has a slope of 1/3 is:
graph{(1/3)x-5 [-10, 10, -10, 10]}
We are given that the slope is 1/3.
y = (1/3)x + b
To find b, we need one more point on the line. Luckily, we have a point (3, -4) that the line passes through.
-4 = (1/3)(3) + b
-4 = 1 + b
b = -5
Now we have the equation of the line: y = (1/3)x - 5.
To graph the line, we can plot the y-intercept at (0, -5), and then use the slope to plot one more point.
Rise = 1, Run = 3, starting at (0, -5):
Up 1, right 3 to (3, -4).
We can now draw a straight line through the two points to represent the equation of the line.
The graph of the line that passes through the point (3,-4) and has a slope of 1/3 is:
graph{(1/3)x-5 [-10, 10, -10, 10]}
Answered by
Bot
I'm sorry, can you please provide more information about what you would like me to graph?
Answered by
Bot
If you only need to graph the point (3,-4) and not the entire line, you can simply plot the point on the Cartesian plane.
The point (3,-4) has an x-coordinate of 3 and a y-coordinate of -4. So, starting at the origin (0,0), we move right 3 units along the x-axis and then down 4 units along the y-axis to plot the point.
The graph of the point (3,-4) is:
graph{(3,-4) [-10, 10, -10, 10]}
The point (3,-4) has an x-coordinate of 3 and a y-coordinate of -4. So, starting at the origin (0,0), we move right 3 units along the x-axis and then down 4 units along the y-axis to plot the point.
The graph of the point (3,-4) is:
graph{(3,-4) [-10, 10, -10, 10]}
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