To graph the line, we can use the formula y = mx + b, where m is the slope and b is the y-intercept.
We are given that the slope is 1/3.
y = (1/3)x + b
To find b, we need one more point on the line. Luckily, we have a point (3, -4) that the line passes through.
-4 = (1/3)(3) + b
-4 = 1 + b
b = -5
Now we have the equation of the line: y = (1/3)x - 5.
To graph the line, we can plot the y-intercept at (0, -5), and then use the slope to plot one more point.
Rise = 1, Run = 3, starting at (0, -5):
Up 1, right 3 to (3, -4).
We can now draw a straight line through the two points to represent the equation of the line.
The graph of the line that passes through the point (3,-4) and has a slope of 1/3 is:
graph{(1/3)x-5 [-10, 10, -10, 10]}
Which is the graph of the line that passes through a point (3,-4) and has a slope of 1/3?
5 answers
Graph
I'm sorry, can you please provide more information about what you would like me to graph?
Graph (3,-4)
and has a slope of 1/3
and has a slope of 1/3
If you only need to graph the point (3,-4) and not the entire line, you can simply plot the point on the Cartesian plane.
The point (3,-4) has an x-coordinate of 3 and a y-coordinate of -4. So, starting at the origin (0,0), we move right 3 units along the x-axis and then down 4 units along the y-axis to plot the point.
The graph of the point (3,-4) is:
graph{(3,-4) [-10, 10, -10, 10]}
The point (3,-4) has an x-coordinate of 3 and a y-coordinate of -4. So, starting at the origin (0,0), we move right 3 units along the x-axis and then down 4 units along the y-axis to plot the point.
The graph of the point (3,-4) is:
graph{(3,-4) [-10, 10, -10, 10]}