Question

On a graph a dot is on 0 line goes up to 4 then right one block then down to 3 back up to 4 and over right one block what would the interval be and then the rate of change is negative over the interval [___,___]

Answer 1

(0,4) then right (1,4) then down to 3 back up from (3,4) to the right one space (5)

Answer 2

No the dot is only on the x-axis at 0 then gooes up at an angle where there is a dot on 4 moves over one space for another dot on the 4 then angled down to right with dot on 3(x-axis) then back up at an angle to 4 again over one space to the 4 again
If you want to coordinates they 0 no y axis then 1,4 but no dot on 1, then 2,4 again no dot on 2, down to 3 no y axis back up to 4,4 but no dot on x axis over one to right on 5,4 no dot on 5

Answer 3

Again the there are 6 dots 0,4,4,3,4 and 4

Answer 4

Thanks but again the coordinates that you put up are wrong maybe I can do it

Answer 5

To analyze the description of the graph you've provided, we can break down the movements:

1. **Starting at (0, 0)**, the dot moves:
2. **Up to (0, 4)**.
3. **Right to (1, 4)**.
4. **Down to (1, 3)**.
5. **Back up to (1, 4)**.
6. **Over right to (2, 4)**.

Now we can put together the coordinates for each segment:
- From (0, 0) to (0, 4): This segment is **vertical**, and the rate of change is **undefined**, as x does not change.
- From (0, 4) to (1, 4): This segment is **horizontal**, with a rate of change of **0**, as y does not change.
- From (1, 4) to (1, 3): This segment is **vertical**, with an undefined rate of change.
- From (1, 3) to (1, 4): This segment is **vertical**, with an undefined rate of change.
- Finally, from (1, 4) to (2, 4): This segment is **horizontal**, with a rate of change of **0**.

**Identifying intervals where the rate of change is negative**:
- The rate of change is only negative during the segment where it moves from (1, 4) to (1, 3). However, we can treat this step as occurring over an interval of x, which remains constant as x moves from 1 to 1 (a vertical movement). In terms of y values decreasing from 4 to 3 with respect to constant x, we can identify the points as:
- **At the point (1, 4)** where you start moving down to (1, 3).

Thus, we can say that the negative rate of change occurs in the interval where y is transitioning from 4 to 3, specifically, we can consider the interval for the x-coordinate with respect to vertical movement:
- **The interval is [1, 1]**, as the movement is only vertically down without changing x.

To summarize:
- The **interval** for the negative rate of change is **[1, 1]**.

So, the answer for the interval where the rate of change is negative is **[1, 1]**.

Answer 6

Let's clarify the movements on the graph based on your description:

1. Start at **(0, 0)**.
2. Move up to **(0, 4)**.
3. Move right to **(1, 4)**.
4. Move down to **(1, 3)**.
5. Move back up to **(1, 4)** again.
6. Finally, move right to **(2, 4)**.

However, based on your latest input, it seems there was a slight misunderstanding. Let's clarify it again:

1. Start at **(0, 4)**.
2. Then, move **right** to **(1, 4)**.
3. Move **down** to **(1, 3)**.
4. Move **back up** to **(1, 4)**.
5. Move **right** to **(2, 4)**.
6. Finally, you specify moving **right again to (5, 4)**.

Let's visualize this path:

- Start at **(0, 4)**: A point at y = 4.
- Then go to **(1, 4)**: This is horizontal, so the rate of change is 0.
- Then go down to **(1, 3)**: Here, the change from y = 4 to y = 3 is a decrease, making the rate of change negative as y decreases while x is constant.
- Move back up to **(1, 4)**: This will have a rate of change that is positive.
- Then, move right to **(2, 4)**: Again, moving horizontally, the rate of change is 0.
- Finally, move right to **(5, 4)**: This segment remains horizontal, contributing another rate of change of 0.

### Analyzing the Negative Rate of Change
The only part of the path where the rate of change is negative occurs when moving from:
- **(1, 4)** to **(1, 3)**.

This means we can define the interval over which the rate of change is negative:

- It occurs in the interval where x remains constant at **1**, while y moves from **4 to 3**.

So, we can say that the interval for the negative rate of change is:

**\[1, 1\]** (since x remains constant during that movement).

### Summary
- The interval where the rate of change is negative is **[1, 1]**.

Answer 7

Thank you for the clarification. Let's outline the movements clearly based on your description:

1. Start at the point **(0, 0)** — this is the origin on the x-axis.
2. Move **upward diagonally** to the point **(1, 4)** — this is where you have a dot.
3. Move **horizontally** to the point **(2, 4)** — there is no dot here.
4. Move **downward diagonally** to the point **(2, 3)** — again, no dot on this point.
5. Move **upward diagonally** back to the point **(2, 4)** — once more, no dot on this point.
6. Move **horizontally** to the point **(5, 4)** — no dot at this point.

### Analyzing the Coordinates and Movements:
Based on these movements, we have the following coordinates:
- **(0, 0)**: Start
- **(1, 4)**: Dot
- **(2, 4)**: No dot
- **(2, 3)**: No dot (when going down)
- **(2, 4)**: No dot (when going back up)
- **(5, 4)**: No dot

### Finding the Intervals:
Now let's break down where the rate of change is positive and negative:

1. From **(0, 0)** to **(1, 4)**:
- This is an upward movement. The rate of change is positive.

2. From **(1, 4)** to **(2, 4)**:
- This is a horizontal movement. The rate of change is 0.

3. From **(2, 4)** to **(2, 3)**:
- This is a downward movement. The rate of change is negative.

4. From **(2, 3)** back to **(2, 4)**:
- This is an upward movement. The rate of change is positive.

5. From **(2, 4)** to **(5, 4)**:
- This is again a horizontal movement. The rate of change is 0.

### Summary of the Intervals with Negative Rate of Change:
The only segment of the path where the rate of change is negative:
- Between **(2, 4)** and **(2, 3)**.

The x-coordinate remains constant at **2** while moving downwards from **4 to 3**.

Thus, the interval for the negative rate of change is:
**\[2, 2\]**.

### Final Answer:
- The interval where the rate of change is negative is **[2, 2]**.

Answer 8

Thank you for your patience and clarification. Let’s summarize everything correctly with the six specific dots and their respective coordinates based on your input:

### Coordinates of Dots
1. **Dot 1** at **(0, 0)** (start)
2. **Dot 2** at **(1, 4)**
3. **Dot 3** at **(2, 4)**
4. **Dot 4** at **(2, 3)**
5. **Dot 5** at **(2, 4)** (back up)
6. **Dot 6** at **(5, 4)**

### Path Description
1. Start at **(0, 0)**.
2. Move **upward** to **(1, 4)** – (Dot 2).
3. Move **right** to **(2, 4)** – (Dot 3).
4. Move **down** to **(2, 3)** – (Dot 4).
5. Move **up** to **(2, 4)** again – (Dot 5).
6. Move **right** to **(5, 4)** – (Dot 6).

### Analyzing the Rate of Change
Now, let's identify where the rate of change is negative:

1. **From (0, 0) to (1, 4):**
- Positive rate of change (upward).

2. **From (1, 4) to (2, 4):**
- Rate of change is 0 (horizontal movement, no change in y).

3. **From (2, 4) to (2, 3):**
- Negative rate of change (y decreases from 4 to 3 while x remains constant at 2).

4. **From (2, 3) to (2, 4):**
- Positive rate of change (upward from 3 to 4).

5. **From (2, 4) to (5, 4):**
- Rate of change is 0 again (horizontal movement).

### Summary of Negative Rate of Change
The only interval where the rate of change is negative is:
- Between **(2, 4)** and **(2, 3)**.

### Final Answer
The interval where the rate of change is negative is:
- **[2, 2]** (indicating that the rate of change is negative while x is 2, as y moves from 4 to 3).

Thank you for your clarification; hopefully, this accurately reflects your intended description!

Answer 9

I apologize for misunderstanding your description earlier. Please go ahead and provide the coordinates or clarify the details, and I'll do my best to assist you based on the information you give. Thank you for your patience!