Graph the ellipse and locate the foci.

16x^2 +9y^2= 144

1 answer

if a>b,
x^2/a^2 + y^2/b^2 = 1
has foci at (±c,0) where a^2=b^2+c^2
Similar Questions
  1. What are the foci of the ellipse? Graph the ellipse.start fraction x squared over 49 end fraction plus start fraction y squared
    1. answers icon 1 answer
    1. answers icon 3 answers
  2. Locate the foci of the ellipse. Show your work.x^2/36+y^2/11=1 c^2=a^2-b^2 c^2=36-11 c^2=25 c= ± sqrt25 c= ±sqrt5*5 is this
    1. answers icon 2 answers
  3. I am not too sure about this problem. Can you please help me?Graph the ellipse and locate the foci. 9x^2=144-16y^2 I got (-
    1. answers icon 4 answers
more similar questions