Given the reaction:

Question

Cu2+(aq) + S2-(aq) CuS(s)
What will happen (a) if CuSO4(aq) is added? And (b) if Na2SO4(aq) is added?

A. (a) Nothing; (b) Less product will form
B. (a) Less product will form; (b) Nothing
C. (a) Nothing; (b) More product will form
D. (a) More product will form; (b) Nothing

Answer 1

Adding CuSO4 is adding a common ion (the Cu^2+) so the reaction will shift to the right producing more CuS. Adding Na2SO4 will do nothing. There is no common ion in Na2SO4 and there is nothing to react. So the answer is ........

Answer 2

The answer ia to d to some up what they said.

Answer 3

The answer is D.