To find the y-coordinate of the parabola given the quadratic equation \( y = 5x^2 + 8x + 9 \) when \( x = -3 \), we can substitute \(-3\) for \(x\) in the equation:
\[ y = 5(-3)^2 + 8(-3) + 9 \]
Calculating each term:
- \( (-3)^2 = 9 \)
- \( 5(-3)^2 = 5 \times 9 = 45 \)
- \( 8(-3) = -24 \)
Now, substituting these values back into the equation:
\[ y = 45 - 24 + 9 \]
Now, compute:
\[ y = 45 - 24 = 21 \]
\[ y = 21 + 9 = 30 \]
Thus, when \( x = -3 \), the y-coordinate of the parabola is \( y = 30 \).
Therefore, the point is:
\[ (-3, 30) \]