Question
The quadratic equation 6x^2−x−15=0 in factored form is
A. (3x−5)(2x+3)=0
B. (3x−5)(2x−3)=0
C. (6x+5)(x−1)=0
D. (6x+5)(2x−3)=0
A. (3x−5)(2x+3)=0
B. (3x−5)(2x−3)=0
C. (6x+5)(x−1)=0
D. (6x+5)(2x−3)=0
Answers
Answer
its A not B
Answer
which results in the solutions x=
A. 5/3
B. 5
C. −6/5
D. −5
A. 5/3
B. 5
C. −6/5
D. −5
Answer
and x=
A. 3
B. 1
C. −3
D. −3/2
A. 3
B. 1
C. −3
D. −3/2
Answered by
GPT 3.5
The factored form of the quadratic equation 6x^2−x−15=0 is:
(2x-5)(3x+3) = 0
Therefore, the correct answer is:
B. (3x−5)(2x−3)=0
(2x-5)(3x+3) = 0
Therefore, the correct answer is:
B. (3x−5)(2x−3)=0
Answered by
GPT 3.5
Apologies for the error in my response. You are correct.
The correct factored form of the quadratic equation 6x^2−x−15=0 is:
A. (3x−5)(2x+3)=0
Thank you for pointing that out.
The correct factored form of the quadratic equation 6x^2−x−15=0 is:
A. (3x−5)(2x+3)=0
Thank you for pointing that out.
Answered by
GPT 3.5
To find the solutions for x, we set each factor to equal zero:
1. 3x-5 = 0
3x = 5
x = 5/3
2. 2x+3 = 0
2x = -3
x = -3/2
Therefore, the correct solutions for x are:
A. 5/3
C. -3/2
1. 3x-5 = 0
3x = 5
x = 5/3
2. 2x+3 = 0
2x = -3
x = -3/2
Therefore, the correct solutions for x are:
A. 5/3
C. -3/2
Answered by
GPT 3.5
To find the solutions for x, we set each factor to equal zero:
1. 3x - 5 = 0
3x = 5
x = 5/3
2. 2x + 3 = 0
2x = -3
x = -3/2
Therefore, the correct solutions for x are:
A. 5/3
D. -3/2
1. 3x - 5 = 0
3x = 5
x = 5/3
2. 2x + 3 = 0
2x = -3
x = -3/2
Therefore, the correct solutions for x are:
A. 5/3
D. -3/2
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