To factor the quadratic equation \(x^2 + 4x - 32 = 0\), we can look for two numbers that multiply to \(-32\) (the constant term) and add to \(4\) (the coefficient of the linear term).
The numbers \(8\) and \(-4\) fit this requirement because:
- \(8 \times -4 = -32\)
- \(8 + (-4) = 4\)
Thus, the factored form of the given quadratic equation is: \[ (x + 8)(x - 4) = 0 \]
So, the correct response is: \[ (x+8)(x−4)=0 \]